MATHS (SOLVED IN STEPS)

Problems on Age - (Page -1)

4. A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?

Problems on Age - (Page -1)

1. A man's age is 125% of what it was 10 years ago, but 83 1/3 % of what it will be after ten 10 years. What is his present age?

**Answer : Option C**

**Explanation :**

Let the age before 10 years = x

Then 125x/100 = x + 10

=>125x = 100x + 1000

=> x = 1000/25 = 40

Present age = x + 10 = 40 +10 = 50

Present age = x + 10 = 40 +10 = 50

2.
Ten years ago, R was half of S in age. If the ratio of their present ages is
3:4, what will be the total of their present ages?

A.
45 B. 40
C. 35 D. 30

**Answer : Option C**

**Explanation :**Let the present age of R and S be 3x and 4x respectively. Ten years ago, R was half of S in age

=>
(3x – 10) = ½ (4x – 10)

=> 6x – 20 = 4x – 10

=> 2x = 10

=> x = 5

total
of their present ages = 3x + 4x = 7x = 7 × 5 = 35

3.
Father is aged three times more than his son Anil. After 8 years, he would be two
and a half times of Anil's age. After further
8 years, how many times would he be of Anil's age?

A.
4 times B. 5 times C. 2 times
D. 3 times

**Answer :**

**Option C**

**Explanation :**

Assume
that Anil's present age = x.

Then
father's present age = 3x + x = 4x

After
8 years, fathers age = 2 ½ times of Anils' age

=>
(4x+8) = 2 ½ × (x+8)

=>
4x + 8 = (5/2) ×(x + 8)

=> 8x + 16 = 5x+ 40

=> 3x = 40-16 = 24

=> x = 24/3 = 8

After
further 8 years,

Anil's
age = x + 8+ 8 = 8+8+8 = 24

Father's
age = 4x + 8 + 8 = 4 × 8 + 8 + 8 = 48

Father's
age/Anil's age = 48/24 = 2

4. A man is 24 years older than his son. In two years, his age will be twice the age of his son. What is the present age of his son?

A.23 B.22
C.21 D.20

**Answer : Option B**

**Explanation :**

Let
the present age of the son = x years

Then
present age the man = (x+24) years

Given
that in 2 years, man's age will be twice the age of his son

=>
(x+24) +2 = 2(x+2)

=>
x = 22

5.
Present ages of Kiran and Syam are in the ratio of 5 : 4 respectively. Three years
hence, the ratio of their ages will become 11 : 9 respectively. What is Syam's present
age in years?

A.28 B.27
C.26 D.24

**Answer : Option D**

**Explanation :**

Ratio
of the present age of Kiran and Syam = 5 : 4

=>
Let the present age of Kiran = 5x

Present
age of Syam = 4x

After
3 years, ratio of their ages = 11:9

=>
(5x + 3) : (4x + 3) = 11 : 9

=>
(5x+3) / (4x+3) = 11/9

=>
9(5x + 3) = 11(4x + 3)

=>
45x + 27 = 44x + 33

=>
x = 33-27 =6

Syam's
present age = 4x = 4×6 = 24

6.
The sum of ages of 5 children born at the intervals of 3 years each is 50 years.
Find out the age of the youngest child?

A.
6 B.5
C.4 D.3

**Answer : Option C**

**Explanation :**

Let
the age of the youngest child = x

Then
the ages of 5 children can be written as x,

(x+3),
(x+6),(x+9) and (x+12)

X
+ (x+3) + (x+6) + (x+9) + (x+12) = 50

=>
5x + 30 =50

=>
5x = 20

=>
x = 20/5 = 4

7.
A is two years older than B who is twice as old as C. The total of the ages of A,
B and C is 27. How old is B?

A.10 B.9 C.8
D.7

**Answer : Option A**

**Explanation :**

Let
the age of C = x. Then

Age
of B = 2x

Age
of A = 2 + 2x

The
total age of A,B and C =27

=>
(2+2x) + 2x + x = 27

=>
5x = 25

=>
25/5 = 5

B's
age = 2x = 2×5 = 10

8. The Average age of a class of 22 students is 21 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher?

8. The Average age of a class of 22 students is 21 years. The average increased by 1 when the teacher's age also included. What is the age of the teacher?

A. 48 B. 45 C. 43 D. 44

**Answer : Option D**

**Explanation :**

Total age of all students = 22×21

Total age of all students + age of the teacher = 23 × 22

Age of the teacher = 23×22 – 22×21 = 22(23-21) = 22×2 = 44

< PROBLEMS ON TRAINS ><Next Page> 01, 02, 03, 04, >< HOME PAGE

Click here---> MATHS (SOLVED IN STEPS)==>HCF & LCM <> PROFIT AND LOSS <> PROBLEMS ON TRAINS <> Problems on Age

Age of the teacher = 23×22 – 22×21 = 22(23-21) = 22×2 = 44

**(Continue....)**< PROBLEMS ON TRAINS ><Next Page> 01, 02, 03, 04, >< HOME PAGE

**>**Click here---> MATHS (SOLVED IN STEPS)==>HCF & LCM <> PROFIT AND LOSS <> PROBLEMS ON TRAINS <> Problems on Age

__PSC GENERAL SCIENCE QUESTIONS AND ANSWERS__
1. General Science - Physics

2. General Science Chemistry

3. General Science Biology

4. General Science Zoology

5. General Science Questions and Answers

6. ARITHMETIC AND MENTAL ABILITY

7. MATHS (SOLVED IN STEPS) => HCF & LCM <> PROFIT AND LOSS <> PROBLEMS ON TRAINS <> Problems on Age

1. PSC CURRENT AFFAIRS-2015 (2000 FACTS)---> Click here

2. PSC PREVIOUS / SOLVED QUESTION PAPERS ---> Click here

3. PSC GENERAL KNOWLEDGE QUESTIONS AND ANSWERS ---> Click here

4. IT, CYBER LAWS AND GENERAL ENGLISH QUESTIONS AND ANSWERS ---> Click here

2. General Science Chemistry

3. General Science Biology

4. General Science Zoology

5. General Science Questions and Answers

6. ARITHMETIC AND MENTAL ABILITY

7. MATHS (SOLVED IN STEPS) => HCF & LCM <> PROFIT AND LOSS <> PROBLEMS ON TRAINS <> Problems on Age

__Related Post__1. PSC CURRENT AFFAIRS-2015 (2000 FACTS)---> Click here

2. PSC PREVIOUS / SOLVED QUESTION PAPERS ---> Click here

3. PSC GENERAL KNOWLEDGE QUESTIONS AND ANSWERS ---> Click here

4. IT, CYBER LAWS AND GENERAL ENGLISH QUESTIONS AND ANSWERS ---> Click here

## No comments:

## Post a Comment